PMC:3475482 / 8467-8828 JSONTXT

{"project":"BLAH6-GNI-CORPUS","denotations":[{"id":"T165","span":{"begin":353,"end":360},"obj":"protein"},{"id":"T166","span":{"begin":199,"end":201},"obj":"DNA"},{"id":"T167","span":{"begin":184,"end":186},"obj":"DNA"},{"id":"T168","span":{"begin":176,"end":178},"obj":"DNA"},{"id":"T169","span":{"begin":77,"end":89},"obj":"DNA"},{"id":"T170","span":{"begin":68,"end":70},"obj":"DNA"},{"id":"T171","span":{"begin":59,"end":61},"obj":"DNA"}],"text":"Definition 6 (Pattern information)\nGiven a pattern P = P1, P2, ..., Pq and a DNA sequence database D, the pattern information of P in D is defined as I(P) = -log|C|Pr(P,D) = I(P1) + I(P2) +......+ I(Pq).\nFor example, the pattern information of pattern \"ATCG\" is I(ATCG,D) = I(A,D) + I(T,D) + I(C,D) + I(G,D) = 1.228 + 0.713 + 1.098 + 0.9365 = 3.9755 in Table 1."}

{"project":"BLAH6-GNI-CORPUS2","denotations":[{"id":"T42","span":{"begin":353,"end":360},"obj":"protein"},{"id":"T43","span":{"begin":294,"end":295},"obj":"protein"},{"id":"T44","span":{"begin":264,"end":268},"obj":"protein"},{"id":"T45","span":{"begin":253,"end":257},"obj":"protein"},{"id":"T46","span":{"begin":199,"end":201},"obj":"DNA"},{"id":"T47","span":{"begin":184,"end":186},"obj":"DNA"},{"id":"T48","span":{"begin":176,"end":178},"obj":"DNA"},{"id":"T49","span":{"begin":164,"end":166},"obj":"protein"},{"id":"T50","span":{"begin":162,"end":163},"obj":"protein"},{"id":"T51","span":{"begin":77,"end":89},"obj":"DNA"},{"id":"T52","span":{"begin":68,"end":70},"obj":"DNA"},{"id":"T53","span":{"begin":59,"end":61},"obj":"DNA"},{"id":"T54","span":{"begin":55,"end":57},"obj":"DNA"},{"id":"T55","span":{"begin":55,"end":61},"obj":"protein"}],"text":"Definition 6 (Pattern information)\nGiven a pattern P = P1, P2, ..., Pq and a DNA sequence database D, the pattern information of P in D is defined as I(P) = -log|C|Pr(P,D) = I(P1) + I(P2) +......+ I(Pq).\nFor example, the pattern information of pattern \"ATCG\" is I(ATCG,D) = I(A,D) + I(T,D) + I(C,D) + I(G,D) = 1.228 + 0.713 + 1.098 + 0.9365 = 3.9755 in Table 1."}