
PMC:7074654 / 3062-3394
Annnotations
{"target":"https://pubannotation.org/docs/sourcedb/PMC/sourceid/7074654","sourcedb":"PMC","sourceid":"7074654","source_url":"https://www.ncbi.nlm.nih.gov/pmc/7074654","text":"imal} \\usepackage{amsmath} \\usepackage{wasysym} \\usepackage{amsfonts} \\usepackage{amssymb} \\usepackage{amsbsy} \\usepackage{upgreek} \\usepackage{mathrsfs} \\setlength{\\oddsidemargin}{-69pt} \\begin{document} }{}$\\alpha$\\end{document} = isolation rate = 6 6.49 6.31–6.66\nLiu et al.3 China and overseas 23 January 2020 Statistical e","divisions":[{"label":"td","span":{"begin":253,"end":257}},{"label":"td","span":{"begin":259,"end":268}},{"label":"td","span":{"begin":269,"end":280}},{"label":"td","span":{"begin":282,"end":300}},{"label":"td","span":{"begin":302,"end":317}}],"tracks":[{"project":"LitCovid-PD-CHEBI","denotations":[{"id":"T4","span":{"begin":210,"end":215},"obj":"Chemical"}],"attributes":[{"id":"A4","pred":"chebi_id","subj":"T4","obj":"http://purl.obolibrary.org/obo/CHEBI_30216"},{"subj":"T4","pred":"source","obj":"LitCovid-PD-CHEBI"}]}],"config":{"attribute types":[{"pred":"source","value type":"selection","values":[{"id":"LitCovid-PD-CHEBI","color":"#ccec93","default":true}]}]}}